DU Admission Question Solution 2006 [A unit]

  1. The correct spelling is –

protractor

protactor

 protector

potactor

  1. The train arrives exactly at midday. It’s always —

in time

before time

late

 on time

  1. ‘Patricide’ is —

The crime of denying one’s own land

 The crime of killing one’s own father

the crime of loving one’s own country too much

an insect killer

  1. The antonym for ‘cacophony ‘is —

irony

 euphony

telephony

symphony

  1. choose the correct pair of words . A good book — with a hard cover to — its contents.

 covered ,wear

hidden , reveal

written , hide

designed , protect

  1. The manager of the company is somewhat susceptible — flattery .

 to

of

with

for

  1. the old road goes — the village.

aginst

under

over

 through

  1. He goes to school — foot.

 on

by

in

with

  1. He made — few mistakes.

an

the

 a

no article

  1. This book is — one I was looking for .

an

the

 a

no article

  1. I — finished my letter yet.

am not

had not

 have not

did not

  1. He oftern — me , but has never– to me.

one who eats

one who gathers

one who demands

 one who buys

  1. Have you — that clock?

wind

 wound

winded

wouded

  1. The manager of the company is somewhat susceptible — flattery .

 to

of

with

for

  1. He often ______ me, but as never ____ to me .

sees , speaks

looks, talks

looked, spoke

 sees , spoken

  1. choose an acceptable English translation for the Bengali sentence – āϤ⧁āĻŽāĻŋ āĻ•āĻŋ āχāĻ‚āϰ⧇āϜāĻŋāϤ⧇ āϕ⧋āύ āϛ⧇āϞ⧇āϭ⧁āϞāĻžāύ⧋ āĻ›ā§œāĻž āϜāĻžāύ⧋?

You do know any nursery rhyme in English

 Do you know any nursery rhyme in English

You know any English verse to forget boys, do you?

Do you know any English forgetfulness verse for boys?

Question 17 ,18 ,19 and 20 are based on the following reading.

Advertising has become a very specialized activity in modern times. In the business world  of today . supply is usually greater than demand . There is great competition between  different manufacturers of the same kind of product to buy their own particular brand . They always have to remind the consumer of the  name  and qualities of their  product. They do this by advertising. The manufactuere  advertises in the product in commercial radio programmes. He employs attractive sales- girls to distribute samples  of it. He  organizes competitions, with prize for the winners. He often advertises on the screens of local cinemas. Most  important of all , in countries that have television he has advertisements put  into programmes that will accept them.

  1. what do sales girls do?

sell goods

put goods on sale

distribute goods around

 distribute samples

  1. ‘specialized ‘ here stands for

specially planned

crafty

unique

 specially selected

  1. ‘consumer ‘ means

radio programmes that buy advertisements

radio programmes that deal with commerce

radio programmes that take money from advertisers .

 radio programmes that sell advertisements

  1. There are — kinds of advertisements mentioned in the passage.

five

six

 seven

eight

  1. This book is — one I was looking for.

a

an

 the

no article

  1. choose the correct interrogative form :

when did you have you last class?

when have your last class?

 when did you have your last class?

when did your last class have?

  1. choose the correct interrogative form :

when is you going to arrive ?

when you going to arrive?

 when are you going to arrive ?

when you are going to arrive?

  1. I was annoyed : — I kept quiet

then

when

still

 and

  1. He is going berserk

He is becoming to someone forcefully

 beat a drum

teach something to someone intensely

beat something like a drum

  1. Choose the correct sentence :

They hardly speaking English

They hardly talk English

They cannot hardly speak English

 They can hardly speak English

  1. choose the correct affirmative sentence of , “He did not apply for the job through proper channel.”

He applied through proper channel

He applied for a different job

  1. 28. He is trying to give up smoking,— ?

 isn’t he

is he

won’t he

will he

  1. The girl broke the cup , —?

 did she

didn’t she

hadn’t she

hasn’t she

  1. Choose the correct sentence :

Neither Bob nor John are responsible for it

 Neither bob nor John is responsible for it

Neither Bob nor John were responsible for it

Neither Bob nor John help responsible for it .

He should have applied through proper channel

 He applied through a different channel

 

  1. āĻ•āĻžāĻŽāĻžāϞ, āϏāĻžāύāĻ‡ā§ŸāĻžāϤ, āϞ⧇āύāĻŋāύ āĻ“ āĻŽā§āϏ⧋āϞāĻŋāύāĻŋāϰ āύāĻžāĻŽ āφāϛ⧇ āϕ⧋āύ āϞ⧇āĻ–āĻžā§Ÿ?

āϏāĻžāĻšāĻŋāĻ¤ā§āϝ⧇ āϖ⧇āϞāĻž

āĻ­āĻžāώāĻžāϰ āĻ•āĻĨāĻž

āĻāϕ⧁āĻļ⧇āϰ āĻ—āĻ˛ā§āĻĒ

 āϝ⧌āĻŦāύ⧇āϰ āĻ—āĻžāύ

  1. āϰ⧋āĻĻā§āϝāĻžāρ āϕ⧇ āĻ›āĻŋāϞ⧇āύ?

āĻĢāϰāĻžāϏāĻŋ āϚāĻŋāĻ¤ā§āϰāĻļāĻŋāĻ˛ā§āĻĒā§€

āĻĢāϰāĻžāϏāĻŋ āύāĻžāĻŸā§āϝāĻ•āĻžāϰ

āĻĢāϰāĻžāϏāĻŋ āĻ•āĻŦāĻŋ

 āĻĢāϰāĻžāϏāĻŋ āĻ­āĻžāĻ¸ā§āĻ•āϰ

  1. ‘āϏ⧋āύāĻžāϰ āϤāϰ⧀’ āĻ•āĻŦāĻŋāϤāĻž āϕ⧋āύ āĻ›āĻ¨ā§āĻĻ⧇ āϰāϚāĻŋāϤ?

āĻ¸ā§āĻŦāϰāĻŦ⧃āĻ¤ā§āϤ

 āĻŽāĻžāĻ¤ā§āϰāĻžāĻŦ⧃āĻ¤ā§āϤ

āĻ…āĻ•ā§āώāϰāĻŦ⧃āĻ¤ā§āϤ

āĻ¸ā§āĻŦāϰāĻŽāĻžāĻ¤ā§āϰāĻŋāĻ•

  1. ‘āĻŽāĻžāύ⧁āώ āĻŽāϰ⧇ āϗ⧇āϞ⧇ āĻĒāĻšā§‡ āϝāĻžā§Ÿ āĨ¤ āĻŦ⧇āρāĻšā§‡ āĻĨāĻžāĻ•āϞ⧇ āĻŦāĻĻāϞāĻžā§Ÿ āĨ¤ āĻ•āĻžāϰāϪ⧇ āĻ…āĻ•āĻžāϰāϪ⧇ āĻŦāĻĻāϞāĻžā§Ÿ āĨ¤ āϏāĻ•āĻžāϞ⧇ āĻŦāĻŋāĻ•āĻžāϞ⧇ āĻŦāĻĻāϞāĻžā§ŸāĨ¤ ‘ āĻ āϏāĻ‚āϞāĻžāĻĒ āĻ•āϰ⧇?

 āύāĻŦāĻžāϰ āϏ⧁āϜāĻžāωāĻĻā§āĻĻ⧌āϞāĻžāϰ

āύāĻŦāĻžāĻŦ āύāĻœā§€āĻŦāωāĻĻā§āĻĻ⧌āϞāĻžāϰ

āχāĻŦā§āϰāĻžāĻšāĻŋāĻŽ āĻ•āĻžāĻ°ā§āĻĻāĻŋāϰ

āφāĻšāĻŽāĻĻ āĻļāĻžāĻš āφāĻŦāĻĻāĻžāϞ⧀āϰ

  1. ‘āφāϜāĻžāύ āĻ–ā§ā§œāĻž ‘ āĻŦāϞ⧇ āĻ•āĻžāϕ⧇ āϏāĻŽā§āĻŦā§‹āϧāύ āĻ•āϰāĻž āĻšā§Ÿā§‡āϛ⧇?

āφāĻŽāĻŋāύ⧁āĻĻā§āĻĻāĻŋ

āĻšāĻžāϰāĻžāϧāύ

āĻšā§‹āϏ⧇āύ āĻŽāĻŋ⧟āĻž

 āϧāύāĻžā§āϜ⧟

  1. ‘āϤāĻšāĻŦāĻŋāϞ ‘ āϕ⧋āύ āĻ­āĻžāώāĻžāϰ āĻļāĻŦā§āĻĻ ?

 āφāϰāĻŦāĻŋ

āϤ⧁āĻ°ā§āĻ•āĻŋ

āωāĻ°ā§āĻĻ⧁

āĻĢāĻžāϰāϏāĻŋ

  1. āĻļ⧁āĻĻā§āϧ āĻŦāĻžāύāĻžāύ āϕ⧋āύāϟāĻŋ ?

āĻĒāĻŋāĻĒāĻŋāϞ⧀āĻ•āĻž

āĻĒā§€āĻĒāĻŋāϞāĻŋāĻ•āĻž

āĻĒāĻŋāĻĒāĻŋāϞāĻŋāĻ•āĻž

 āĻĒāĻŋāĻĒā§€āϞāĻŋāĻ•āĻž

  1. āĻļ⧁āĻĻā§āϧ āĻļāĻŦā§āĻĻāϗ⧁āĻšā§āĻ› āĻšāĻšā§āϛ⧇-

 āωāϚāĻŋāϤ , āφāĻšā§ƒāϤ, āϚāϞ , āĻŽāĻšāĻžāϰāĻĨ

āωāϚāĻŋā§Ž, āφāĻšāϰāĻŋāϤ, āϏāϚāϞ, āϏāĻšāĻžāϰāĻĨā§€

āωāϚāĻŋā§Ž, āφāĻšā§ƒāϤ, āϏāϚāϞ, āĻŽāĻšāĻžāϰāĻĨā§€

āωāϚāĻŋāϤ, āφāĻšāϰāĻŋāϤ, āϚāϞ, āĻŽāĻšāĻžāϰāĻĨ

  1. āωāĻĒāϏāĻ°ā§āĻ—āϜāĻžāϤ āĻļāĻŦā§āĻĻ –

āĻ…āĻžā§āϜāϞāĻŋ

āĻ…āĻ™ā§āϕ⧁āϰ

āĻ…āύāĻļāύ

 āĻ…āύāĻžāϚāĻžāϰ

  1. ‘āϏāĻĻā§āϝ⧋āϜāĻžāϤ’ āĻļāĻŦā§āĻĻ⧇āϰ āϏāĻ¨ā§āϧāĻŋāĻŦāĻŋāĻšā§āϛ⧇āĻĻ –

āϏāĻĻā§āϝ + āϜāĻžāϤ

 āϏāĻĻā§āϝāσ + āϜāĻžāϤ

āϏāĻĻā§āϝāĻž + āϜāĻžāϤ

āϏāĻĻāĻž + āϞāĻžāĻ­

  1. āĻāĻ•āĻžāϧāĻŋāĻ• āωāĻĒāϏāĻ°ā§āĻ—āϝāĻžā§‡āϗ⧇ āĻ—āĻ āĻŋāϤ āĻļāĻŦā§āĻĻ āϕ⧋āύāϟāĻŋ?

 āĻ…āύāϤāĻŋāĻŦ⧃āĻšā§Ž

āĻĒā§āϰāĻŦāĻŋāĻˇā§āϟ

āĻ…āĻŦāϞ⧋āĻ•āύ

āĻ…āĻ—āĻŖāϤāĻžāĻ¨ā§āĻ¤ā§āϰāĻŋāĻ•

  1. ‘āĻ•āĻŋāĻŖāĻžāĻ™ā§āĻ•’ āĻļāĻŦā§āĻĻ⧇āϰ āĻ…āĻ°ā§āĻĨ āϕ⧀?

āφāρāϚāĻŋāϞ

āϤāĻŋāϞ

āĻ•ā§āώāϤ

 āĻ•ā§œāĻž

  1. āϏāĻžāϧ⧁ āĻ“ āϚāϞāĻŋāϤ āϰ⧀āϤāĻŋāϤ⧇ āĻ…āĻ­āĻŋāĻ¨ā§āύāϰ⧁āĻĒ⧇ āĻŦā§āϝāĻŦāĻšā§ƒāϤ āĻšā§Ÿ –

āĻ…āĻŦā§āϝ⧟

 āϏāĻŽā§āĻŦā§‹āϧāύ āĻĒāĻĻ

āϏāĻ°ā§āĻŦāύāĻžāĻŽ

āĻ•ā§āϰāĻŋ⧟āĻž

  1. ‘āĻ•ā§āϰāĻŋāϕ⧇āϟ āϖ⧇āϞ⧇’ āĻŦāĻžāĻ•ā§āϝ⧇āϰ āύāĻŋāĻŽā§āύāϰ⧇āĻ– āĻļāĻŦā§āĻĻ⧇āϰ āĻ•āĻžāϰāĻ• āĻ“ āĻŦāĻŋāĻ­āĻ•ā§āϤāĻŋ-

āĻ•āĻ°ā§āϤāĻžā§Ÿ āĻļā§‚āĻ¨ā§āϝ

 āĻ•āĻ°ā§āĻŽā§‡ āĻļā§‚āĻ¨ā§āϝ

āĻ•āϰāϪ⧇ āĻļā§‚āĻ¨ā§āϝ

āĻ…āϧāĻŋāĻ•āϰāύ⧇ āĻļā§‚āĻ¨ā§āϝ

  1. āϏāĻžāϧ⧁ āĻ­āĻžāώāĻžā§Ÿ āϞāĻŋāĻ–āĻŋāϤ āύāĻŋāĻŽā§āύ⧋āĻ•ā§āϤ āĻŦāĻžāĻ•ā§āϝāϟāĻŋāϤ⧇ āϭ⧁āϞ⧇āϰ āϏāĻ‚āĻ–ā§āϝāĻž āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰāĨ¤ ‘āĻ…āύāĻžāĻ—āϤ āĻ­āĻŦāĻŋāĻˇā§āϝāϤ⧇āϰ āĻŦāĻŋāώ⧟ āĻŦāĻŋāĻŦ⧇āϚāύāĻž āĻ•āϰ⧇ āϗ⧁āĻŖā§€āϰāĻž āϝāĻž āĻŦāϞāĻŋāϞ⧇āύ , āωāĻĒāĻ¸ā§āĻĨāĻŋāϤ āϜāύāĻ—āĻŖāϰāĻž āĻ¤ā§ŽāĻ•ā§āώāĻŖāĻžāϤ āϤāĻžāĻš āϏāĻŽāĻ°ā§āĻĨāύ āĻ•āϰ⧇āĻ›āĻŋāϞ ?

āϤāĻŋāύ

āϚāĻžāϰ

āĻĒāĻžāρāϚ

 āĻ›ā§Ÿ

  1. ‘Scanner ‘ āĻŦā§‹āĻāĻžā§Ÿ –

 āϏ⧂āĻ•ā§āĻˇā§āĻŽ āĻĒāϰ⧀āĻ•ā§āώāĻž āϝāĻ¨ā§āĻ¤ā§āϰ

āϧāĻžāύāĻŽāĻžā§ā§œāĻžāχ āϝāĻ¨ā§āĻ¤ā§āϰ

āĻŽā§āĻĻā§āϰāĻŖ āϝāĻ¨ā§āĻ¤ā§āϰ

āĻ•āĻŽā§āĻĒāĻŋāωāϟāĻžāϰ

  1. ‘āϏāĻšā§‡āĻˇā§āϟ’ āĻļāĻŦā§āĻĻ⧇āϰ āĻŦāĻŋāĻĒāϰ⧀āϤ āĻļāĻŦā§āĻĻ āϕ⧀?

āĻĒā§āϰāĻšā§‡āĻˇā§āϟ

āĻ¸ā§āĻŦāύāĻŋāĻˇā§āĻ 

 āύāĻŋāĻļā§āĻšā§‡āĻˇā§āϟ

āĻ…āĻ•āĻ°ā§āĻŽāĻŖā§āϝ

  1. āϕ⧋āύāϟāĻŋ āĻļ⧁āĻĻā§āϧ āĻļāĻŦā§āĻĻ ?

āĻļāĻļ⧁āϰ

 āĻļā§āĻŦāĻļ⧁āϰ

āĻļā§āĻŦāϏ⧁āϰ

āĻļāĻļ⧁⧜

  1. ‘āϞ⧋āĻ•āϟāĻž āĻĒ⧁āϰ⧋ āĻ•āĻžāρāĻ āĻžāϞāϟāĻžāχ āĻ–ā§‡ā§Ÿā§‡ āĻĢ⧇āϞ⧇āϞ’āĨ¤ āĻāχ āĻŦāĻžāĻ•ā§āϝ⧇ ‘āĻ–ā§‡ā§Ÿā§‡ āĻĢ⧇āϞāϞ’ āϕ⧋āύ āϧāϰāύ⧇āϰ āĻ•ā§āϰāĻŋ⧟āĻžāĻĒāĻĻ?

āĻ…āϏāĻŽāĻžāĻĒāĻŋāĻ•āĻž āĻ•ā§āϰāĻŋ⧟āĻž

āĻ…āĻ•āĻ°ā§āϤ⧃āĻ• āĻ•ā§āϰāĻŋ⧟āĻž

āĻ…āĻ•āĻ°ā§āĻŽāĻ• āĻ•ā§āϰāĻŋ⧟āĻž

 āϝ⧌āĻ—āĻŋāĻ• āĻ•ā§āϰāĻŋ⧟āĻž

  1. āĻĒāĻžāĻ°ā§āĻļā§āĻŦāĻŋāĻ• āĻŦā§āϝāĻžā§āϜāύ⧇āϰ āωāĻĻāĻžāĻšāϰāĻŖ āϕ⧋āύāϟāĻŋ?

āĻš

āĻļ

āϰ

 āϞ

  1. ‘āĻĒāϰāĻŋāĻ¤ā§āϝāĻ•ā§āϤ āĻŦāĻžā§œāĻŋ āϚāĻŋāύāϤ⧇ āĻĻ⧇āϰāĻŋ āĻšā§Ÿā§‡ āύāĻž āĨ¤ āĻ•āĻŋāĻ¨ā§āϤ⧁ āĻāĻŽāύ āĻŦāĻžā§œāĻŋ āĻĒāĻžāĻ“ā§ŸāĻž āύāĻŋāϤāĻžāĻ¨ā§āϤ āϏ⧌āĻ­āĻžāĻ—ā§āϝ⧇āϰ āĻ•āĻĨāĻžāĨ¤’ āĻāĻ•āϟāĻŋ āϤ⧁āϞāϏ⧀ āĻ—āĻžāϛ⧇āϰ āĻ•āĻžāĻšāĻŋāύ⧀’ āĻ—āĻ˛ā§āĻĒ⧇ āωāĻ•ā§āϤāĻŋāϟāĻŋ āĻ•āĻžāϰ?

āĻ•āĻžāĻĻ⧇āϰ⧇āϰ

āĻŦāĻĻāϰ⧁āĻĻā§āĻĻāĻŋāύ⧇āϰ

 āϞ⧇āĻ–āϕ⧇āϰ

āĻŽā§‹āĻĻāĻžāĻŦā§āĻŦ⧇āϰ⧇āϰ

  1. ‘āĻĢāĻŋāϰ⧇ āĻāϏ⧇ āĻĻ⧇āĻ–āĻŋ āϏ⧋āύāĻžāϰ āĻĒā§āϰāϤāĻŋāĻŽāĻž āϞ⧁āϟāĻžā§Ÿ āĻĒāĻĨ⧇āϰ āĻĒāϰ⧇āĨ¤’ āĻ•āĻŦāϰ’ āĻ•āĻŦāĻŋāϤāĻžāϰ āĻ āϏ⧋āύāĻžāϰ āĻĒā§āϰāϤāĻŋāĻŽāĻž āĻšāϞ⧋ –

āĻŦ⧃āĻĻā§āϧ⧇āϰ āĻ¸ā§āĻ¤ā§āϰ⧀

āĻŦ⧃āĻĻā§āϧ⧇āϰ āĻĒ⧁āĻ¤ā§āϰāĻŦāϧ⧁

āĻŦ⧃āĻĻā§āϧ⧇āϰ āύāĻžāϤāύāĻŋ

 āĻŦ⧃āĻĻā§āϧ⧇āϰ āĻŽā§‡ā§Ÿā§‡

  1. ‘āύāĻŋāĻœā§‡āχ āϚāĻŽāϕ⧇ āωāĻ āĻŋ. āϕ⧀ āύāĻŋāĻ¸ā§āĻĒ⧃āĻš, āϕ⧇āĻŽāύ āĻļā§€āϤāϞ ‘ āĨ¤ āĻ āĻĒāĻ™āĻ•ā§āϤāĻŋāϰ āϰāϚ⧟āĻŋāϤāĻž āĻšāϞ⧇āύ-

āφāĻšāϏāĻžāύ āĻšāĻžāĻŦā§€āĻŦ

āϏ⧁āĻĢāĻŋ⧟āĻž āĻ•āĻžāĻŽāĻžāϞ

 āĻļāĻžāĻŽāϏ⧁āϰ āϰāĻšāĻŽāĻžāύ

āĻ…āĻŽā§ŸāĻŋ āϚāĻ•ā§āϰāĻŦāĻ°ā§āϤ⧀

  1. āĻŦāĻŋā§Ÿā§‡āϰ āϏāĻŽā§Ÿ āĻšā§ˆāĻŽāĻ¨ā§āϤ⧀ āĻ“ āϤāĻžāϰ āĻ¸ā§āĻŦāĻžāĻŽā§€āϰ āĻŦ⧟āϏ āĻ›āĻŋāϞ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ –

ā§§ā§§ āĻ“ ā§§ā§Ŧ

ā§§ā§Š āĻ“ ā§§ā§­

ā§§ā§Ģ āĻ“ ā§§ā§Ž

Â ā§§ā§­ āĻ“ ⧧⧝

  1. ‘āϕ⧇āϞāĻŋāύ⧁ āĻļ⧈āĻŦāĻžāϞ⧇’ āϭ⧁āϞāĻŋ āĻ•āĻŽāύ-āĻ•āĻžāύāύ’ āĨ¤ āĻāĻ–āĻžāύ⧇ ‘āĻ•āĻŽāϞ-āĻ•āĻžāύāύ’ āĻļāĻŦā§āĻĻ⧇āϰ āĻŦā§āϝāĻžā§āϜāύāĻžāĻ°ā§āĻĨ –

 āĻŦāĻžāĻ‚āϞāĻž āĻ­āĻžāώāĻž

āχāĻ‚āϰ⧇āϜāĻŋ āĻ­āĻžāώāĻž

āĻĢāϰāĻžāϏāĻŋ āĻ­āĻžāώāĻž

āĻĒāĻĻā§āĻŽāĻŦāύ

  1. āύāĻŋāĻšā§‡āϰ āϕ⧋āύāϟāĻŋ ‘āϜ⧁āρāχ’ āĻāϰ āϏāĻŽāĻžāĻ°ā§āĻĨāĻ• āĻļāĻŦā§āĻĻ?

āĻĒā§āϰāϏ⧂āύ

āĻ‡ā§ŸāĻžāϏāĻŽāĻŋāύ

āϜāĻžāĻĢāϰāĻžāύ

 āĻŦ⧇āϞāĻŋ

  1. ‘āϤ⧁āĻŽāĻŋ āϝ⧇āϤ⧇ āĻĒāĻžāϰāĻŦ⧇ āύāĻžāĨ¤’ āĻ āĻŦāĻžāĻ•ā§āϝ⧇āϰ āĻ…āĻ¸ā§āϤāĻŋāĻŦāĻžāϚāĻ• āϰ⧁āĻĒ āϕ⧋āύāϟāĻŋ?

‌āϤ⧁āĻŽāĻŋ āϝ⧇āϤ⧇ āĻĒāĻžāϰāĻŦ⧇

 āϤ⧋āĻŽāĻžāϕ⧇ āĻĨāĻžāĻ•āϤ⧇ āĻšāĻŦ⧇

āϤ⧋āĻŽāĻžāϕ⧇ āϝ⧇āϤ⧇ āĻšāĻŦ⧇

āϤ⧁āĻŽāĻŋ āύāĻž āĻ—āĻŋā§Ÿā§‡ āĻĒāĻžāϰāĻŦ⧇ āύāĻž

  1. ” The medicine will pull you round ” āĻŦāĻžāĻ•ā§āϝāϟāĻŋāϰ āĻŦāĻ™ā§āĻ—āĻžāύ⧁āĻŦāĻžāĻĻ –

āĻ“āώ⧁āϧāϟāĻŋ āϤ⧋āĻŽāĻžāϰ āĻ•āĻžāĻœā§‡ āφāϏāĻŦ⧇ āύāĻž

āĻ“āώ⧁āϧāϟāĻŋ āϤ⧋āĻŽāĻžāϰ āĻ•ā§āώāϤāĻŋ āĻ•āϰāĻŦ⧇

āĻ“āώ⧁āϧāϟāĻŋāϰ āĻĒā§āϰāϤāĻŋāĻ•ā§āϰāĻŋ⧟āĻž āĻšāĻŦ⧇ āϤ⧋āĻŽāĻžāϰ āĻ“āĻĒāϰ

 āĻ“āώ⧁āϧāϟāĻŋ āϤ⧋āĻŽāĻžāϕ⧇ āĻ­āĻžāϞ⧋ āĻ•āϰ⧇ ‌āĻĻ⧇āĻŦ⧇

  1. ‘āĻŦāĻžāϜāĻžāϰ⧇ āĻ•āĻžāϟāĻž’ āĻŦāĻžāĻ—āϧāĻžāϰāĻžāϰ āĻ…āĻ°ā§āĻĨ-

āĻ–ā§āϝāĻžāϤāĻŋ āĻ…āĻ°ā§āϜāύ āĻ•āϰāĻž

āύāĻžāĻŽāϝāĻļ āĻšāĻ“ā§ŸāĻž

 āĻŦāĻŋāĻ•ā§āϰāĻŋ āĻšāĻ“ā§ŸāĻž

āĻ•āĻŽ āĻŽā§‚āĻ˛ā§āϝ⧇ āĻŦāĻŋāĻ•ā§āϰāĻŋ āĻ•āϰāĻž

  1. āϰāĻŦā§€āĻ¨ā§āĻĻā§āϰāύāĻžāĻĨ⧇āϰ āϞ⧇āĻ–āĻž āĻ—ā§āϰāĻ¨ā§āĻĨ āϕ⧋āύāϟāĻŋ?

āĻĒāĻ˛ā§āϞ⧀āϏāĻŽāĻžāϜ

āϏāύ⧇āϟ āĻĒāĻžā§āϚāĻžāĻļā§Ž

 āĻ•āĻžāϞāĻžāĻ¨ā§āϤāϰ

āĻ›āĻžā§ŸāĻžāĻžāύāϟ

 

  1. C2H5OH  C2H5OHāϜāĻžāϰāĻŋāϤ āĻšā§Ÿā§‡ ‘Z’ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āĻ•āϰ⧇ āϝāĻžÂ Â Â Â C2H5OH     C2H5OH   āĻāϰ āϏāĻžāĻĨ⧇ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻž āĻ•āϰ⧇ āĻāĻˇā§āϟāĻžāϰ āϤ⧈āϰ⧀ āĻ•āϰ⧇āĨ¤ Z āĻ•āĻŋ?

HCOOH

CH3COOH          CH3COOH

CH3CH2COOH    CH3CH2COOH

CH3COOC2H5 CH3COOC2H5

  1. āĻ—ā§āϰāĻŋāĻ—āύāĻžāĻ°ā§āĻĄ āĻŦāĻŋāĻ•āĻžāϰāϕ⧇āϰ āϏāĻžāĻĨ⧇CH3OH   CH3OHāĻāϰ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžā§Ÿ āĻ•āĻŋ āĻšā§Ÿ?

 Alkane

Ether

Ester

Aldehyde

  1. āύāĻŋāĻŽā§āύ⧇āϰ āĻ–ā§‹āϞāĻž āĻļāĻŋāĻ•āϞ āϝ⧌āĻ—āϗ⧁āϞāĻŋāϰ āϕ⧋āύāϟāĻŋāϤ⧇ āϏāĻŦāϗ⧁āϞ⧋ āĻŦāĻ¨ā§āϧāύāĻ‡âˆ‚âˆ‚(āϏāĻŋāĻ—āĻŽāĻž) ?

C10H20C10H20

 C10H22C10H22

C10 H18    C10 H18

C10  H20O       C10  H20O

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āϝ⧌āĻ—āϟāĻŋāϰ āĻāĻ•āϟāĻŋ āĻŦāĻ¨ā§āϧāύsp3−sp sp3-sp āĻšāĻžāχāĻŦā§āϰāĻŋāĻĄ āĻ…āϰāĻŦāĻŋāϟāĻžāϞ⧇āϰ āĻ…āϧāĻŋāĻ•ā§āϰāĻŽāύ⧇āϰ āĻĢāϞ⧇ āϏ⧃āĻˇā§āϟāĻŋ āĻšā§Ÿā§‡āϛ⧇?

CH3−C≡C−H CH3-C≡C-H

CH3 CH=CHCH3 CH3 CH=CHCH3

H−C≡C−H   H-C≡C-H

CH3CH2CH2CH3CH3CH2CH2CH3

  1. RCOR→RCH2R   RCOR→RCH2R   āϰāĻžāϏāĻžā§ŸāύāĻŋāĻ• āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāύ⧇āϰ āϜāĻ¨ā§āϝ āϕ⧋āύ āĻŦāĻŋāĻ•āĻžāϰāϟāĻŋ āĻĒā§āĻ°ā§Ÿā§‹āϜāύ?

H2SO4  H2SO4

K2Cr2O7K2Cr2O7

NaBH4 NaBH4

 Zn/Hg.  cone HCL Zn/Hg.  cone HCL

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžāϟāĻŋāϰKp=Kc?       Kp=Kc?

PCl5(g)⇔PCl3(g) +Cl2(g) PCl5(g)⇔PCl3(g) +Cl2(g)

N2(g)  + 3 H2(g) ⇔2NH3(g)      N2(g)  + 3 H2(g) ⇔2NH3(g)

2HI(g) ⇔H2(g) + I2(g)       2HI(g) ⇔H2(g) + I2(g)

CO(g) + 2H2(g) ⇔CH3OH(g)       CO(g) + 2H2(g) ⇔CH3OH(g)

  1. āĻāĻ•āϟāĻŋ āĻĢāϞ⧇āϰ āϰāϏ āĻšāĻžāχāĻĄā§āϰ⧋āĻœā§‡āύ āĻ†ā§Ÿāύ⧇āϰ āϘāύāĻ¤ā§āĻŦ3.3×10−2M3.3×10-2M    āĻšāϞ⧇ āϐ āϰāϏ⧇āĻ°Â Â pH pH āĻ•āϤ?

2.00

 1.48

4.48

2.18

  1. āĻ•āĻĒāĻžāϰ āϏāĻžāϞāĻĢ⧇āĻŸā§‡āϰ āϜāĻ˛ā§€ā§Ÿ āĻĻā§āϰāĻŦāϪ⧇ 10 ampere āĻŦāĻŋāĻĻā§āĻ¯ā§ā§Ž 30 āĻŽāĻŋāύāĻŋāϟ āϧāϰ⧇ āϚāĻžāϞāύāĻž āĻ•āϰāϞ⧇ āĻ•ā§āϝāĻžāĻĨā§‹āĻĄā§‡ āĻ•āĻŋ āĻĒāϰāĻŋāĻŽāĻžāĻŖ āĻ•āĻĒāĻžāϰ āϜāĻŽāĻž āĻšāĻŦ⧇?

12.0 g

 6.0 g

3.0 g

9.0 g

  1. N2(g) + 3H2(g) ⇔2NH3(g) N2(g) + 3H2(g) ⇔2NH3(g) āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžāϟāĻŋāĻ°Â Â Â Â Â Â KpKc     KpKc āĻāϰ āĻŽāĻ§ā§āϝ⧇ āϏāĻŽā§āĻĒāĻ°ā§āĻ•āϟāĻŋ āĻšāϞ –

Kp=Kc(RT)2        Kp=Kc(RT)2

   Kp=Kc(RT)2  Kp=Kc(RT)2

Kp=Kc(RT)−1         Kp=Kc(RT)-1

Kp=Kc(RT)Kp=Kc(RT)

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧇āĻžāύ āĻŦāĻ¸ā§āϤ⧁āϰ āĻ•āĻŖāĻžāϗ⧁āϞ⧋āϰ āĻļ⧁āϧ⧁āĻŽāĻžāĻ¤ā§āϰ āĻ•āĻŽā§āĻĒāύ-āĻ—āϤāĻŋ āĻ°ā§Ÿā§‡āϛ⧇?

 NaCl(s)

H2O(I)   H2O(I)

H2O(g)      H2O(g)

H2(g)  H2(g)

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžā§Ÿ āϚāĻžāĻĒ āĻŦ⧃āĻĻā§āϧāĻŋāϰ āĻĢāϞ⧇ āϏāĻžāĻŽā§āϝāĻžāĻŦāĻ¸ā§āĻĨāĻžā§Ÿ āĻ‰ā§ŽāĻĒāĻžāĻĻāύ⧇āϰ āĻĒāϰāĻŋāĻŽāĻžāĻŖ āĻŦ⧃āĻĻā§āϧāĻŋ āĻĒāĻžā§Ÿ ?

H2(g)+Br2(g)⇔2HBr(g)    H2(g)+Br2(g)⇔2HBr(g)

2NO2(g) +7H2(g) ⇔2 NH3(g)  + 4H2O (g)  2NO2(g) +7H2(g) ⇔2 NH3(g)  + 4H2O (g)

 CO2(g)   + C (s) ⇔2CO(g)  CO2(g)   + C (s) ⇔2CO(g)

CaCO3(s) ⇔CaO(s) +CO2(s)    CaCO3(s) ⇔CaO(s) +CO2(s)

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āχāϞ⧇āĻ•āĻŸā§āϰ⧋āĻĄāϟāĻŋāϰ āĻĒā§āϰāĻŽāĻžāĻŖ āĻŦāĻŋāϜāĻžāϰāĻŖ āĻĒāĻŸā§‡āύāĻļāĻŋ⧟āĻžāϞ āϏāĻ°ā§āĻŦā§‹āĻšā§āϚ?

H+(aq) /H2(g) ,pt  H+(aq) /H2(g) ,pt

Cu2(aq)/Cu(s) Cu2(aq)/Cu(s)

Na+(aq) /Na(s)           Na+(aq) /Na(s)

       Pt/F2(g) F−(aq)           Pt/F2(g) F-(aq)

  1. āύāĻŋāĻšā§‡āϰ āϕ⧋āύāϟāĻŋ āĻŦāĻžāĻĢāĻžāϰ āĻĻā§āϰāĻŦāĻŖ?

CH3COOH & NaOH CH3COOH & NaOH

      CH3COOH & CH3COONa     CH3COOH & CH3COONa

NaOH  & Na2CO2     NaOH  & Na2CO2

HCl & NaCl       HCl & NaCl

  1. āĻ•āĻˇā§āϟāĻŋāĻ• āϏ⧋āĻĄāĻž āĻĻā§āϰāĻŦāϪ⧇āϰ āĻĒā§āϰāϤāĻŋ āϞāĻŋāϟāĻžāϰ⧇ 5 āĻ—ā§āϰāĻžāĻŽ NaOH āĻĨāĻžāĻ•āϞ⧇ āĻĻā§āϰāĻŦāĻŖāϟāĻŋāϰ āĻŽā§‹āϞāĻžāϰāĻŋāϟāĻŋ āĻ•āϤ?

1.25 M

12.5 M

 0.125 M

1.52 M

  1. āϚāĻžāĻĒ āĻ¸ā§āĻĨāĻŋāϰ āϰ⧇āϖ⧇ āĻāĻ•āϟāĻŋ āĻ—ā§āϝāĻžāϏ⧇āϰ (āĻ†ā§ŸāϤāύ 1000cm3cm3    ) āϤāĻžāĻĒāĻŽāĻžāĻ¤ā§āϰāĻž āĻ…āĻ°ā§āϧ⧇āĻ• āĻ•āϰāĻž āĻšāϞāĨ¤ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāĻŋāϤ āĻ…āĻŦāĻ¸ā§āĻĨāĻžā§Ÿ āωāĻšāĻžāϰ āĻ†ā§ŸāϤāύ āĻ•āϤ āĻšāĻŦ⧇?

2000cm3    2000cm3

 500 cm3 500 cm3

1000cm3 1000cm3

1500 cm31500 cm3

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϝ⧌āĻ—āϗ⧁āϞāĻŋāϰ āĻŽāĻ§ā§āϝ⧇ āϕ⧋āύāϟāĻŋ āĻ†ā§ŸāύāĻŋāĻ• āĻŦ⧈āĻļāĻŋāĻˇā§āĻŸā§āϝ āϏāĻŦāĻšā§‡ā§Ÿā§‡ āĻŦ⧇āĻļā§€?

SiF4     SiF4

AlCl3     AlCl3

Nal Nal

 CsF CsF

  1. āύāĻŋāĻŽā§āύ⧋āĻ•ā§āϤ d- āĻŦā§āϞāĻ• āĻŽā§ŒāϞāϏāĻŽā§‚āĻšā§‡āϰ āϕ⧋āύāϟāĻŋāϤ⧇ 4s āĻ…āϰāĻŦāĻŋāϟāĻžāϞ⧇ 1 āϟāĻŋ āχāϞ⧇āĻ•āĻŸā§āϰāύ āĻ°ā§Ÿā§‡āϛ⧇?

Mn(25)

Fe (26)

Ni (28 )

 Cu(29)

  1. 2p āĻ…āϰāĻŦāĻŋāϟāĻžāϞ⧇āϰ n, 1 āĻāĻŦāĻ‚ m āĻāϰ āĻŽāĻžāύ āĻšāĻšā§āϛ⧇ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ –

2,1,2

 2,1,(-1,0,1)

2,2(-2)

1,1,0

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϝ⧌āĻ—āϗ⧁āϞ⧋āϰ āϕ⧋āύāϟāĻŋāϰ āϕ⧇āĻ¨ā§āĻĻā§āĻ°ā§€ā§Ÿ āĻĒāϰāĻŽāĻžāϪ⧁ āĻ…āĻ•āĻŸā§‡āϟ āύāĻŋ⧟āĻŽ āĻ…āύ⧁āϏāϰāĻŖ āĻ•āϰ⧇ āύāĻž?

CCl4CCl4

      XeF2        XeF2

H2O   H2O

NF3            NF3

  1. āϕ⧋āύ āχāϞāĻ•āĻŸā§āϰāύāĻŋāĻ• āĻ¸ā§āĻĨāĻžāύāĻžāĻ¨ā§āϤāϰ⧇āϰ āĻĢāϞ⧇ āĻšāĻžāχāĻĄā§āϰ⧋āĻœā§‡āύ āĻŦāĻ°ā§āĻŖāĻžāϞ⧀āϰ ‘āĻŦāĻžāĻŽāĻžāϰ’ āϏāĻŋāϰāĻŋāĻœā§‡āϰ 4th āϞāĻžāχāύ⧇āϰ āϏ⧃āĻˇā§āϟāĻŋ āĻšā§Ÿ?

 n=6 to n = 2

n= 5 to n = 2

n=4 to n =1

n =4 to n = 0

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϝ⧌āĻ—āϗ⧁āϞ⧋āϰ āĻŽāĻ§ā§āϝ⧇ āϏāĻŦāĻšā§‡ā§Ÿā§‡ āĻŦ⧇āĻļā§€ āĻ…āĻŽā§āĻ˛ā§€ā§Ÿ āĻšāϞ –

  Cl3CCOOH Cl3CCOOH

Cl2CHCOOH    Cl2CHCOOH

ClCH2COOH      ClCH2COOH

CH3CH2CH−COOH      CH3CH2CH-COOH

  1. āύāĻŋāĻŽā§āύāϰ āϕ⧋āύāϟāĻŋ āĻœā§āϝāĻžāĻŽāĻŋāϤāĻŋāĻ• āϏāĻŽāĻžāϪ⧁āϤāĻž āĻĒā§āϰāĻĻāĻ°ā§āĻļāύ āĻ•āϰ⧇ ?

CH2=CH−CH3 CH2=CH-CH3

CH3CH(OH)COOH      CH3CH(OH)COOH

  CH3CH=CH−CH3 CH3CH=CH-CH3

CH3 CH2CH=CH2  CH3 CH2CH=CH2

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύāϟāĻŋ āĻ“āϜāύ⧀āĻ•āϰāĻŖ āĻ“ āφāĻ°ā§āĻĻā§āϰ āĻŦāĻŋāĻļā§āϞ⧇āώāϪ⧇āϰ āĻĢāϞ⧇ āĻļ⧁āϧ⧁āĻŽāĻžāĻ¤ā§āϰ āĻāĻ•āϟāĻŋ āĻ‰ā§ŽāĻĒāĻžāĻĻ āĻĻ⧇āĻŦ⧇?

 CH3C(CH3)=C(CH3)−CH3CH3C(CH3)=C(CH3)-CH3

CH3CH=CH(CH3)−CH3CH3CH=CH(CH3)-CH3

CH3C(CH3)=CH−CH2−CH5CH3C(CH3)=CH-CH2-CH5

CH2=CH(CH3)−CH(CH3)−CH3CH2=CH(CH3)-CH(CH3)-CH3

  1. āύāĻŋāĻŽā§āύ⧇āϰ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžāϰ āĻŽā§‚āϞ āĻ‰ā§ŽāĻĒāĻžāĻĻ āĻ•āĻŋ?

 

 

 

 

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύāϟāĻŋ āĻœā§āϝāĻžāĻŽāĻŋāϤāĻŋāĻ• āϏāĻŽāĻžāϪ⧁āϤāĻž āĻĒā§āϰāĻĻāĻ°ā§āĻļāύ āĻ•āϰ⧇?

CH2=CH−CH3CH2=CH-CH3

CH3CH(OH)COOHCH3CH(OH)COOH

 CH3CH=CH−CH3CH3CH=CH-CH3

CH3CH2CH−COOHCH3CH2CH-COOH

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧇āĻžāύāϟāĻŋ āϜāĻžāϰāĻŖ -āĻŦāĻŋāϜāĻžāϰāĻŖ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻž āύ⧟?

H2S + Cl2→2HCl + S H2S + Cl2→2HCl + S

      CuSO4 + 2NH4OH→Cu(OH)2 +  (NH4)2 SO4        CuSO4 + 2NH4OH→Cu(OH)2 +  (NH4)2 SO4

4HCl + MnO2 →Cl2 + MnCl2 + 2H2O     4HCl + MnO2 →Cl2 + MnCl2 + 2H2O

2H2O + 2Cl2→4HCl + O2 2H2O + 2Cl2→4HCl + O2

  1. 8.0 cm3Na2CO3      8.0 cm3  Na2CO3       āĻāϰ āĻĻā§āϰāĻŦāĻŖāϕ⧇ āϏāĻŽā§āĻĒā§‚āĻ°ā§āĻŖāϰ⧁āĻĒ⧇ āĻĒā§āϰāĻļāĻŽāύ āĻ•āϰāϤ⧇ 10.0  cm3 cm3 1.0 M HCl āĻĻā§āϰāĻŦāϪ⧇āϰ āĻĒā§āĻ°ā§Ÿā§‹āϜāύ āĻšā§Ÿ āĨ¤Â Na2CO3Na2CO3 āĻĻā§āϰāĻŦāĻŖāϟāĻŋāϰ āϘāύāĻŽāĻžāĻ¤ā§āϰāĻž āĻšāĻšā§āϛ⧇ –

 0.625 M

1.0 M

0.025 M

0.6 M

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āϏ⧇āĻŸā§‡āϰ āϧāĻžāϤ⧁āϗ⧁āϞāĻŋ āĻ¸ā§āĻŸā§‡āχāύāϞ⧇āϏ āĻ¸ā§āĻŸā§€āϞ⧇ āĻŦāĻŋāĻĻā§āϝāĻŽāĻžāύ?

 Fe, Cr & Ni

Fe, Cr & Cu

Cu, Zn & Ni

Cu, Sn & Pb

  1. āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύāϟāĻŋ āĻĨ⧇āϕ⧇ āĻāĻ•āϟāĻŋ āχāϞ⧇āĻ•āĻŸā§āϰāύ āĻ…āĻĒāϏāĻžāϰāϪ⧇āϰ āϜāĻ¨ā§āϝ⧇ āϏāĻŦāĻšā§‡ā§Ÿā§‡ āĻŦ⧇āĻļāĻŋ āĻļāĻ•ā§āϤāĻŋ āĻĒā§āĻ°ā§Ÿā§‹āϜāύ?

Ar

 Al3+ Al3+

Na+   Na+

Cl−Cl-

  1. āύāĻŋāĻŽā§āύ⧇āϰ āĻŦāĻŋāĻ•ā§āϰāĻŋ⧟āĻžā§Ÿ āωāĻĒāĻžāĻĻāĻžāύ ‘p’ āĻāĻŦāĻ‚ ‘Q’ āϕ⧋āύ āϏ⧇āĻŸā§‡ āĻŦāĻŋāĻĻā§āϝāĻŽāĻžāύ ?CH3CH2CH(OH)CH3I2OH−−−−→ P (aq)  + Q (s)    CH3CH2CH(OH)CH3 →I2OH- P (aq)  + Q (s)

CH3CH2CH3,CH4 respectively  CH3CH2CH3,CH4 respectively

 CH3CH2COO−,CHI3 respectively CH3CH2COO-,CHI3 respectively

CH3CH3, CH3CH3 respectively CH3CH3, CH3CH3 respectively

CH3CH2CH2CH3CH3, I2 respectively CH3CH2CH2CH3CH3, I2 respectively

 

 

  1. (2,2)-2x),(1,2) āĻāĻŦāĻ‚ (2,b-2x) āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϗ⧁āϞ⧋ āϏāĻŽāϰ⧇āĻ– āĻšāϞ⧇, b – āĻāϰ āĻŽāĻžāύ –

-1

1

 2

-2

  1. āϝāĻĻāĻŋA=(1324)     A=(1324)  āĻšā§Ÿ āϤāĻŦā§‡Â A−1=? A-1=?

12(4−2  −31)   12(4-2  -31)

12(4−3 −21)    12(4-3 -21)

12(4−2 −31)     12(4-2 -31)

  −12(4−3 −21) -12(4-3 -21)

  1. 2(cosx +secx) =5 āϏāĻŽā§€āĻ•āϰāϪ⧇āϰ āϏāĻžāϧāĻžāϰāĻŖ āϏāĻŽāĻžāϧāĻžāύ –

nĪ€Â ÂąĪ€3    nĪ€Â ÂąĪ€3

  2nĪ€ÂąĪ€6  2nĪ€ÂąĪ€6

2nĪ€+Ī€6 2nĪ€+Ī€6

nĪ€Â +Ī€6  nĪ€Â +Ī€6

  1. (4,-2) āĻŦāĻŋāĻ¨ā§āĻĻ⧁ āĻĨ⧇āϕ⧇ 5x +12y =3 āϰ⧇āĻ–āĻžāϰ āωāĻĒāϰ āĻ…āĻ™ā§āĻ•āĻŋāϤ āϞāĻŽā§āĻŦ⧇āϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ-

−713-713

89  89

−89   -89

  713 713

  1. 1 āĻĨ⧇āϕ⧇ 520 āĻĒāĻ°ā§āϝāĻ¨ā§āϤ āϏāĻ‚āĻ–ā§āϝāĻžāϗ⧁āϞ⧋ āĻĨ⧇āϕ⧇ āĻĻ⧈āĻŦāϚ⧟āύ āĻĒāĻĻā§āϧāϤāĻŋāϤ⧇ āĻāĻ•āϟāĻŋ āϏāĻ‚āĻ–ā§āϝāĻž āϚ⧟āύ āĻ•āϰāĻž āĻšāϞ⧇ āϏāĻ‚āĻ–ā§āϝāĻžāϟāĻŋ āϘāύāϏāĻ‚āĻ–ā§āϝāĻž āĻšāĻ“ā§ŸāĻžāϰ āϏāĻŽā§āĻ­āĻŦāύāĻž –

164 164

160  160

   165  165

265  265

  1. āϕ⧋āύ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ āĻĻ⧁āχāϟāĻŋ āĻŦāϞ120∘120°    āϕ⧋āϪ⧇ āĻ•ā§āϰāĻŋ⧟āĻžāĻļā§€āϞ āĨ¤ āĻŦ⧃āĻšāĻ¤ā§āϤāϰ āĻŦāϞāϟāĻŋāϰ āĻŽāĻžāύ 10 N āĻāĻŦāĻ‚ āϤāĻžāĻĻ⧇āϰ āϞāĻŦā§āϧāĻŋ āĻ•ā§āώ⧁āĻĻā§āϰāϤāϰ āĻŦāϞ⧇āϰ āϏāĻžāĻĨ⧇ āϏāĻŽāϕ⧋āĻŖ āĻ‰ā§ŽāĻĒāĻ¨ā§āύ āĻ•āϰāϞ⧇ āĻ•ā§āώ⧁āĻĻā§āϰāϤāϰ āĻŦāϞ⧇āϰ āĻŽāĻžāύ –

4N

 5N

6N

8 N

  1. (x+2x)6(x+2x)6  āĻāϰ āϏāĻŽā§āĻĒā§āϰāϏāĻžāϰāϪ⧇ x āĻŽā§āĻ•ā§āϤ āĻĒāĻĻāϟāĻŋ-

448

120

 240

3000

  1. tan−11 + tan−12 + tan−13 tan-11 + tan-12 + tan-13 āĻāϰ āĻŽāĻžāύ –

0

Ī€2Ī€2

Â Ī€Â Â Ī€

2Ī€Â 2Ī€

  1. xy+x2y2−c=0      xy+x2y2-c=0  āĻšāϞ⧇,  dxdy=? dxdy=?

 −xy-xy

xy    xy

yx   yx

−yx-yx

  1. 3x + 2y + K =0 āϰ⧇āĻ–āĻžāϟāĻŋx2+y2−8x−2y−4=0  x2+y2-8x-2y-4=0  āĻŦ⧃āĻ¤ā§āϤāϕ⧇ āĻ¸ā§āĻĒāĻ°ā§āĻļ āĻ•āϰāϞ⧇ K āĻāϰ āĻāĻ•āϟāĻŋ āĻŽāĻžāύ –

1

27

5

 -1

  1. |7−3x|≤5 |7-3x|≤5 āĻ…āϏāĻŽāϤāĻžāϟāĻŋāϰ āϏāĻŽāĻžāϧāύ –

−53≤x≤73  -53≤x≤73

     23≤x≤4    23≤x≤4

x≤−53  x≤-53

xâ‰Ĩ−73 or x ≤−53   xâ‰Ĩ-73 or x ≤-53

  1. f(x)= 3 +x1−2xf(x) = 3 +x1-2xāĻāĻŦāĻ‚Â Â Â f−1(x)=?     f-1(x)=?

 x−32x+1  x-32x+1

3−x1+2x   3-x1+2x

x+32+x  x+32+x

x+32x+1x+32x+1

  1. (1,4) āĻāĻŦāĻ‚ (9, -12 ) āĻŦāĻŋāĻ¨ā§āĻĻ⧁āĻĻā§āĻŦā§Ÿā§‡āϰ āϏāĻ‚āϝ⧋āĻ—āĻ•āĻžāϰ⧀ āϏāĻ‚āϝ⧋āĻ—āĻ•āĻžāϰ⧀ āϰ⧇āĻ–āĻžāĻ‚āĻļ āĻ…āĻ¨ā§āϤāσāĻ¸ā§āĻĨāĻ­āĻžāĻŦ⧇ āϝ⧇ āĻŦāĻŋāĻ¨ā§āĻĻ⧁āϤ⧇ 5 : 3 āĻ…āύ⧁āĻĒāĻžāϤ⧇ āĻŦāĻŋāĻ­āĻ•ā§āϤ āĻšā§Ÿ āϤāĻžāϰ āĻ¸ā§āĻĨāĻžāύāĻžāĻ™ā§āĻ• –

 (6,-6)

(3,5)

(2,1)

(-6, 5)

  1. x2−3x+5         x2-3x+5  āĻāϰ āĻ¨ā§āϝ⧂āύāϤāĻŽ āĻŽāĻžāύ –

3

5

154   154

 114114

  1. cos230° +cos260°  + …….. + cos2180°             cos230° +cos260°  + …….. + cos2180°      āĻāϰ āĻŽāĻžāύ –

0

2

 3

4

  1. āĻĻā§āĻŦāĻŋāĻŽāĻŋāĻ• āϏāĻ‚āĻ–ā§āϝāĻž 10011010101 āĻāϰ āĻĻāĻļāĻŽāĻŋāϕ⧇ āĻĒā§āϰāĻ•āĻžāĻļ –

1235

 1237

1241

1247

  1. 0.3 + 0.003 + 0.00003 + …. āϧāĻžāϰāĻžāϟāĻŋāϰ āĻ…āϏ⧀āĻŽ āĻĒāĻ°ā§āϝāĻ¨ā§āϤ āϝ⧋āĻ—āĻĢāϞ –

 10331033

13   13

133  133

3310033100

  1. f āϏāĻŽāĻ¤ā§āĻŦāϰāϪ⧇ āĻāĻ•āϟāĻŋ āĻŦ⧇āϞ⧁āύ āωāĻ°ā§āĻ§ā§āĻŦ⧇ āωāĻ āϛ⧇āĨ¤ āĻŦ⧇āϞ⧁āύ⧇āϰ āĻ“āϜāύ⧇āϰ āĻ•āϤ āĻ…āĻ‚āĻļ āĻ•āĻŽāĻžāύ⧋ āĻšāϞ⧇ āĻŦ⧇āϞ⧁āύāϟāĻŋāϰ āĻ¤ā§āĻŦāϰāĻŖ 2 f āĻšāĻŦ⧇ ?

f2g+f  f2g+f

f2g−f  f2g-f

  fg+2f   fg+2f

fg−2f fg-2f

  1. âˆĢĪ€20√1+sonθdθ âˆĢ0Ī€21+sonθ dθ  āĻāϰ āĻŽāĻžāύ –

√2   2

 2

Ī€Â Â Ī€

Ī€2Â Â Â Â Â Â Â Â Ī€2

  1. âˆĢ10dx√2x−x2âˆĢ01 dx2x-x2 āĻāϰ āĻŽāĻžāύ –

Ī€2Â Â Â Â Ī€2

1

Â Â Â Â Â Ī€4Â Â Â Â Ī€4

  1. →F1→F1āĻāĻŦāĻ‚Â Â Â â†’F2  →F2 āĻŦāϞ āĻĻ⧁āχāϟāϰāĻŋ āϞāĻŦā§āϧāĻŋ →F3→F3 ; āϝ⧇āĻ–āĻžāĻ¨ā§‡Â Â â†’F1 =2i∧−3j∧, →F1 =2i∧-3j∧,,        →F2=5i∧+4j∧        →F2=5i∧+4j∧ āĻšāĻ˛ā§‡Â Â Â Â â†’F2=?   →F2=?

−3i∧−7j∧-3i∧-7j∧

7i∧+j∧    7i∧+j∧

7i∧+7j∧ 7i∧+7j∧

       3i∧+7j∧      3i∧+7j∧

  1. ιιāϏ⧂āĻ•ā§āĻˇā§āĻŽāϕ⧋āĻŖ āĻšāϞ⧇, xcosι + ysinι  = 4   xcosι + ysinι  = 4    āĻāĻŦāĻ‚ 4x + 3y = 5 āϏāĻŽāĻžāĻ¨ā§āϤāϰāĻžāϞ āϰ⧇āĻ–āĻžāĻĻā§āĻŦā§Ÿā§‡āϰ āĻĻā§‚āϰāĻ¤ā§āĻŦ-

-1unit

 3 units

1 unit

9 units

  1. limx→0(ex−e−x)2x         limx→0(ex-e-x)2x   āĻāϰ āĻŽāĻžāύ –

0

 1

1/2

Does not exist

  1. āϝāĻĻāĻŋCosA  CosA=45=45 āĻšā§Ÿ, āϤāĻŦā§‡Â Â Â Â Â 1+tan2A1−tan2A    1+tan2A1-tan2A āĻāϰ āĻŽāĻžāύ –

−257-257

75   75

 257257

−75-75

  1. āϝāĻĻāĻŋ f(x) =x2−2âˆŖâˆŖxâˆŖâˆŖÂ Â Â x2-2|x| āĻāĻŦāĻ‚Â Â g(x)=x2+1  g(x)=x2+1  āĻšā§Ÿ, āϤāĻŦā§‡Â Â Â g(f(−2)     g(f(-2)    āĻāϰ āĻŽāĻžāύ –

0

65

5

 1

  1. y=x2y=x2āĻāĻŦāĻ‚ y=2x āĻĻā§āĻŦāĻžāϰāĻž āφāĻŦāĻĻā§āϧ āĻāϞāĻžāĻ•āĻžāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰāĻĢāϞ –

 43 unit243 unit2

34unit2      34unit2

4unit2    4unit2

3unit2  3unit2

  1. āĻāĻ•āϟāĻŋ āĻ—āĻžā§œā§€ āĻ¸ā§āĻĨāĻŋāϰāĻžāĻŦāĻ¸ā§āĻĨāĻž āĻšāϤ⧇ āϏāĻŽāĻ¤ā§āĻŦāϰāϪ⧇ āϚāϞāĻž āĻļ⧁āϰ⧁ āĻ•āϰ⧇ 5 āϏ⧇āϕ⧇āĻ¨ā§āĻĄā§‡ 180 āĻŽāĻŋ. / āϏ⧇. āĻ—āϤāĻŋāĻŦ⧇āĻ— āĻĒā§āϰāĻžāĻĒā§āϤ āĻšāϞāĨ¤ āĻ—āĻžā§œāĻŋāϟāĻŋāϰ āĻ¤ā§āĻŦāϰāĻŖ –

    36m /sec2    36m /sec2

32m/sec2    32m/sec2

30m/sec2     30m/sec2

40m/sec2  40m/sec2

  1. 4i∧+2j∧−3k∧4i∧+2j∧-3k∧āĻāĻŦāĻ‚Â Â Îģi∧−3j∧+2k∧   Îģi∧-3j∧+2k∧   āϭ⧇āĻ•ā§āϟāϰāĻĻā§āĻŦ⧟ āĻĒāϰāĻ¸ā§āĻĒāϰ āϞāĻŽā§āĻŦ āĻšāϞ⧇,       Îģ      Îģ āĻāϰ āĻŽāĻžāύ –

 3

-1

5

2

  1. x>0 , y>0, x + y <6, 2x + y <8 āĻļāĻ°ā§āϤāϏāĻŽā§‚āĻš āϏāĻžāĻĒ⧇āĻ•ā§āώ⧇ z =2x + y āϰāĻžāĻļāĻŋāϟāĻŋāϰ āϏāĻ°ā§āĻŦāύāĻŋāĻŽā§āύ āĻŽāĻžāύ –

 6

10

12

14

  1. i1−111ii1-111iāĻāϰ āĻŽāĻžāύ –

1-i

 1 + i

2i

-1 + i

 

  1. āĻāĻ• āĻ–āĻžāĻĻā§āϝ āĻ¸ā§āϤāϰ āĻĨ⧇āϕ⧇ āĻ…āĻ¨ā§āϝ āĻ–āĻžāĻĻā§āϝ āĻ¸ā§āϤāϰ⧇ āĻļāĻ•ā§āϤāĻŋ āĻĒā§āϰāĻŦāĻžāĻšā§‡āϰ āϏāĻ āĻŋāĻ• āϧāĻžāϰāĻŖāĻž āĻĻā§‡ā§Ÿ āϝ⧇ āĻĒāĻŋāϰāĻžāĻŽāĻŋāĻĄā§ƒā§ƒ āϤāĻž āĻšāϞ⧋ –

Pyramid of biomass

Pyramid of number

Pyramid of dry biomass

 Pyramid of energy

  1. āĻ•ā§āϝāĻžāĻ™ā§āĻ—āĻžāϰ⧁ āϕ⧋āύ āϭ⧌āĻ—ā§‹āϞāĻŋāĻ• āĻ…āĻžā§āϚāϞ⧇āϰ āĻĒā§āϰāĻžāĻŖā§€?

Oriental

 Australian

Ethiopean

Palaearctle

  1. āϕ⧋āύ āϰāĻ•ā§āϤāĻ—ā§āϰ⧁āĻĒ āĻŦāĻšāύāĻ•āĻžāϰ⧀ āĻŦā§āϝāĻ•ā§āϤāĻŋāϕ⧇ ‘āϏāĻžāĻ°ā§āĻŦāϜāύ⧀āύ āĻĻāĻžāϤāĻž’ āĻŦāϞāĻž āĻšā§Ÿ?

B

 O

A

AB

  1. āϏāĻœā§āϜāĻžāĻ•ā§āϰāĻŽāĻžāύ⧁āϝāĻžā§Ÿā§€ āĻŽāĻ§ā§āϝāĻ•āĻ°ā§āϪ⧇āϰ āĻšāĻžā§œāϗ⧁āϞ⧋ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ –

Incus, stapes, Maleus

Stapes, Incus, Maleus

Incus, Maleus, Stapes

 Maleus , Incus , stapes

  1. āωāĻ¤ā§āϤāĻœā§‡āύ⧇āϏāĻŋāϏ⧇ āĻŽā§‹āϟ āĻĒā§‹āϞāĻžāϰ āĻŦāĻĄāĻŋ āϤ⧈āϰāĻŋ āĻšā§Ÿ?

ā§§

⧍

Â ā§Š

ā§Ē

  1. āϕ⧋āύāϟāĻŋ āĻŽāĻŋāĻĨā§‹āĻœā§€āĻŦā§€ āύāĻžāχāĻŸā§āϰ⧋āĻœā§‡āύ āφāĻŦāĻĻā§āϧāĻ•āϰāϪ⧇ āĻ…āĻ‚āĻļ āĻ—ā§āϰāĻšāĻŖ āĻ•āϰ⧇?

Xanthomonas

 Rhizobium

Azotobacter

Agrobacterium

  1. āψāĻ¸ā§āϟ āϰ⧁āϟāĻŋ āϤ⧈āϰāĻŋāϤ⧇ āϕ⧇āύ āĻŦā§āϝāĻŦāĻšā§ƒāϤ āĻšā§Ÿ?

āĻ…ā§āϝāĻžāϞāϕ⧋āĻšāϞ āϤ⧈āϰāĻŋāϰ āϜāĻ¨ā§āϝ

 CO2 āϤ⧈āϰāĻŋāϰ āϜāĻ¨ā§āϝ

O⧍ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰāĻžāϰ āϜāĻ¨ā§āϝ

āϚāĻŋāύāĻŋ āĻŦā§āϝāĻŦāĻšāĻžāϰ āĻ•āϰāĻžāϰ āϜāĻ¨ā§āϝ

  1. ‘āĻ°â€Œā§āϝāĻžāĻŽā§‡āĻ¨ā§āϟāĻž’ āϕ⧋āĻĨāĻžā§Ÿ āωāĻĒāĻ¸ā§āĻĨāĻŋāϤ?

Marchantia

 Pteris

Semibarbula

Selaginella

  1. āĻŦā§āϝāĻ•ā§āϤāĻŋāĻŦā§€āĻœā§€ āωāĻĻā§āĻ­āĻŋāĻĻ⧇āϰ āĻļāĻ¸ā§āϝ āĻ•āĻŋāϰ⧁āĻĒ?

 āĻšā§āϝāĻžāĻĒā§āĻ˛ā§Ÿā§‡āĻĄ

āĻĄāĻŋāĻĒā§āĻ˛ā§Ÿā§‡āĻĄ

āĻ…ā§āϝāĻžāĻŽāĻĢāĻŋāĻĄāĻŋāĻĒā§āĻ˛ā§Ÿā§‡āĻĄ

āĻŸā§āϰāĻŋāĻĒā§āĻ˛ā§Ÿā§‡āĻĄ

  1. āĻ—ā§āϞāĻŋāϏāĻžāϰāĻžāĻ˛ā§āĻĄāĻŋāĻšāĻžāχāĻĄ āĻšāĻšā§āϛ⧇ āĻāĻ•āϟāĻŋ –

Tetrose

 Triose

Ribose

Pentose

  1. āĻœā§‡āϞāĻŋāĻĢāĻŋāϏ⧇āϰ āϞāĻžāĻ°ā§āĻ­āĻžāϰ āύāĻžāĻŽ –

Tornaria

 Ephyra

Trochophore

Ammoecete

  1. āĻ•ā§āϝāĻžāϞāϏāĻŋ⧟āĻžāĻŽ āĻŦāĻĒāĻžāϕ⧇ āϏāĻšāĻžā§ŸāϤāĻžāĻ•āϰ⧀ āĻ—ā§āϰāĻ¨ā§āĻĨāĻŋ āĻšāϞ⧋-

 parathyroid

Adrenal

Pancreas

Pituitary

  1. āϕ⧋āύ āĻ…āĻ¸ā§āĻĨāĻŋāϤ⧇ āĻ“āϞ⧇āĻ•ā§āϰ⧇āύāύ āĻĒā§āϰāϏ⧇āϏ āĻĨāĻžāϕ⧇?

Scapula

Ischium

Humerus

 Ulna

  1. āĻŦ⧃āĻ•ā§āϕ⧇āϰ āφāϞāĻŸā§āϰāĻžāĻĢāĻŋāϞāĻŸā§āϰ⧇āĻļāύ āĻĒāϰāĻŋāϚāĻžāϞāύāĻžāĻ•āϰ⧀ āĻ…āĻ™ā§āĻ— āĻšāϞ⧋ –

LH

Bowmans Caqpsule

Medulla

 Glomerulus

  1. āĻ…āĻ¸ā§āϟāĻŽ āĻ•āϰ⧋āϟāĻŋāĻ• āĻ¸ā§āύāĻžā§Ÿā§āϕ⧇ āĻŦāϞ⧇-

Vagus

 Auditory

Fsacial

Olfactory

  1. Restriction āĻāύāϜāĻžāχāĻŽ āĻāϰ āĻ•āĻžāϜ āĻšāϞ⧋ –

 DNA –āϕ⧇ āϛ⧇āĻĻāύ āĻ•āϰāĻž

DNA āĻœā§‹ā§œāĻž āϞāĻžāĻ—āĻžāύ⧋

DNA -āĻāϰ āϏāĻ‚āĻ–ā§āϝāĻž āĻŦ⧃āĻĻā§āϧāĻŋ

DNA āĻ…āĻ•āĻžāĻ°ā§āϝāĻ•āϰ āĻ•āϰāĻž

  1. āϕ⧋āύāϟāĻŋ āĻāĻŋāĻ˛ā§āϞāĻŋ āφāĻšā§āĻ›āĻžāĻĻāĻŋāϤ āϕ⧋āώāĻžāĻ™ā§āĻ—āĻžāϪ⧁ āύ⧟ ?

 Microtubule

Lysosome

Golgi apparatus

Ribosome

  1. āϤāĻŋāύāϟāĻŋ āϜāĻŋāύ āĻāĻ•āχ āĻšā§‹āĻŽā§‹āϞ⧋āĻ—āĻžāϏ āĻ•ā§āϰ⧋āĻŽā§‹āϏ⧋āĻŽā§‡ āĻ…āĻŦāĻ¸ā§āĻĨāĻžāύ āĻ•āϰāϞ⧇ āϜāĻŋāύāĻ•ā§āϰ⧟āϕ⧇ āĻŦāϞ⧇ –

Epistatic genes

Alleles

Linked genes

 Multiple alleles

  1. āϕ⧋āύ āĻĒāĻ°ā§āĻŦ⧇āϰ āĻĒā§āϰāĻžāĻŖā§€āϤ⧇ āĻ•ā§‹ā§ŸāĻžāύ⧋āϏāĻžāχāϟāϏ āĻĨāĻžāϕ⧇ –

protozoa

Cnidaria

 porifera

Crustacea

  1. āĻ•ā§āώ⧁āĻĻā§āϰāĻžāĻ¨ā§āĻ¤ā§āϰ⧇āϰ āϏāĻ°ā§āĻŦāĻŦāĻšāĻŋā§ŽāĻ¸ā§āĻĨ āĻ•āϞāĻžāĻ¸ā§āϤāϰāϕ⧇ āĻŦāϞ⧇ –

Mucosa

Muscularis mucosa

Submucosa

 Serosa

  1. āϕ⧋āώāĻĒā§āϰāĻžāĻšā§€āϰ āϏāĻŋāϞāĻŋāĻ•āĻžāϝ⧁āĻ•ā§āϤ āĻāĻŦāĻ‚ āĻ•āĻĒāĻžāϟāĻŋāĻ•āĻž āωāĻĒāĻ¸ā§āĻĨāĻŋāϤ āϝ⧇ āĻļ⧈āĻŦāĻžāϞ⧇ āϤāĻžāϰ āύāĻžāĻŽ āĻšāĻšā§āϛ⧇-

 Navicula

Spirogyra

Sargassum

Polysiphonia

  1. āϤāĻŋāϞ āϤ⧇āϞ⧇āϰ āĻ‰ā§ŽāϏ āĻšāϞ⧋ –

Glycine max

 Sesamum indicum

Arachis hypodgaea

Helianthus annuus

  1. āĻ•ā§āϰ⧁āϏāĻŋāĻĢ⧇āϰāĻŋ āĻĒāϰāĻŋāĻŦāĻžāϰāϭ⧁āĻ•ā§āϤ āωāĻĻā§āĻ­āĻŋāĻĻ⧇āϰ āĻ…āĻŽāϰāĻžāĻŦāĻŋāĻ¨ā§āϝāĻžāϏ āĻšāĻšā§āϛ⧇ –

āĻĒā§āϰāĻžāĻ¨ā§āĻ¤ā§€ā§Ÿ

 āĻŦāĻšā§āĻĒā§āϰāĻžāĻ¨ā§āĻ¤ā§€ā§Ÿ

āĻ…āĻ•ā§āĻˇā§€ā§Ÿ

āĻŽā§‚āĻ˛ā§€ā§Ÿ

  1. āĻĢ⧁āϞ āĻšāĻ“ā§ŸāĻž āϏāĻ¤ā§āĻ¤ā§āĻŦ⧇ āϕ⧋āύāϟāĻŋāϕ⧇ āĻĢāϞ āĻŦāϞ⧇ āĻŽāύ⧇ āĻšā§Ÿ?

āĻĄāĻžāϞāĻŋāĻŽ

āφāϤāĻž

 āĻĄā§āĻŽā§āϰ

āĻ•āĻžāρāĻ āĻžāϞ

  1. āĻŽā§ŒāĻŽāĻžāĻ›āĻŋāϰ āĻĒāĻžāϞāύāϕ⧇ āĻŦāϞāĻž āĻšā§Ÿ –

sericulture

lac culture

 Apiculture

Pisciculture

  1. āĻšā§āϝāĻžāϚ āĻ“ āĻ¸ā§āĻ˛ā§āϝāĻžāĻ• āϚāĻ•ā§āϰ⧇ C4 āωāĻĻā§āĻ­āĻŋāĻĻ⧇ āĻĒā§āϰāĻĨāĻŽ āĻ¸ā§āĻĨāĻžā§Ÿā§€ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āϕ⧋āύāϟāĻŋ?

āĻŽā§āϝāĻžāϞāĻŋāĻ• āĻāϏāĻŋāĻĄ

 āĻ…āĻ•ā§āϏāĻžāϞ⧋ āĻāϏāĻŋāϟāĻŋāĻ• āĻāϏāĻŋāĻĄ

āĻĒāĻžāχāϰ⧁āĻ­āĻŋāĻ• āĻāϏāĻŋāĻĄ

āĻĢāϏāĻĢā§‹āĻ—ā§āϞāĻŋāϏāĻžāϰāĻŋāĻ• āĻāϏāĻŋāĻĄ

  1. āϕ⧋āύāϟāĻŋ āĻāĻ•āϟāĻŋ āĻ–āĻžāĻĻā§āϝāĻļ⧃āĻ™ā§āĻ–āϞ āĻāϰ āωāĻĻāĻžāĻšāϰāĻŖ ?

Grass -Nematoe -Tiger

Egg – Larva – Adult

Flower – Fruit- Seed

 Grass- Antelope- Lion

  1. āϕ⧋āύ āωāĻĻā§āĻ­āĻŋāĻĻ āϏ⧁āĻ¨ā§āĻĻāϰāĻŦāύ⧇āϰ āĻŽā§āϝāĻžāύāĻ—ā§āϰ⧋āĻ­ āĻŦāύ⧇ āϜāĻ¨ā§āĻŽā§‡?

Nymphaea nouchali

 Aegiceras carniculatum

Erythrina indica

Acacia nilotica

  1. āϕ⧋āύāϟāĻŋāϤ⧇ āĻŽā§āĻ•ā§āϤ āϏāĻŽāĻĒāĻžāĻ°ā§āĻļā§āĻŦā§€ā§Ÿ āĻ­āĻžāĻ¸ā§āϕ⧁āϞāĻžāϰ āĻŦāĻžāĻ¨ā§āĻĄāϞ āĻĒāĻžāĻ“ā§ŸāĻž āϝāĻžā§Ÿ?

āĻāĻ•āĻŦā§€āϜāĻĒāĻ¤ā§āϰ⧀ āĻ•āĻžāĻ¨ā§āĻĄā§‡

āĻāĻ•āĻŦā§€āϜāĻĒāĻ¤ā§āϰ⧀ āĻŽā§‚āϞ⧇

 āĻĻā§āĻŦāĻŋāĻŦā§€āϜāĻĒāĻ¤ā§āϰ⧀ āĻ•āĻžāĻ¨ā§āĻĄā§‡

āĻĻā§āĻŦāĻŋāĻŦā§€āϜāĻĒāĻ¤ā§āϰ⧀ āĻŽā§‚āϞ⧇

  1. āĻŽā§‡āĻ¨ā§āĻĄā§‡āϞ⧇āϰ ā§§ āĻŽ āϏ⧂āĻ¤ā§āϰāϰ āϜāĻŋāύ⧋āϟāĻžāχāĻĒ⧇āϰ āĻ…āύ⧁āĻĒāĻžāϤ āĻšāĻšā§āϛ⧇ –

ā§Š:ā§§

⧍:⧍

⧍: ⧧: ⧧

Â ā§§: ⧍: ā§§

 

  1. āĻāĻ•āϟāĻŋ āĻ­āĻžāϰ⧀ āϤ⧇āϜāĻˇā§āĻ•ā§āϰāĻŋ⧟ āĻĒāĻĻāĻžāĻ°ā§āĻĨ āφāϞāĻĢāĻž āĻ•āĻŖāĻž āĻŦāĻŋāĻ•āĻŋāϰāĻŖ āĻ•āϰ⧇ āϝāĻžāϰ āĻ­āϰ 10 g āĻāĻ• āĻ…āĻ°ā§āϧāĻžā§Ÿā§ āĻĒāϰ⧇ āĻāϰ āĻ­āϰ āĻšāĻŦ⧇ –

 5g

Almost 10 g

10 g

None of these

  1. āĻāĻ•āϟāĻŋ āϤāĻžāϰāĻ•āĻžāϰ āĻ­āϰ āĻĒāĻžāρāϚ āϏ⧌āϰ āĻ­āϰ⧇āϰ āϏāĻŽāĻžāύ āĨ¤ āϤāĻžāϰāĻ•āĻžāϟāĻŋ āĻ•ā§ƒāĻˇā§āĻŖ āĻŦāĻŋāĻŦāϰ⧇ āĻĒāϰāĻŋāĻŖāϤ āĻšāϞ⧇ āĻāϰ āĻ¸ā§‹ā§ŸāĻžāĻ°ā§āϜāĻ¸ā§āĻ•āĻžāχāĻ˛ā§āĻĄ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ āĻ•āϤ āĻšāĻŦ⧇? āϏ⧂āĻ°ā§āϝ⧇āϰ āĻ­āϰ2×1030kg.G =6.67×10−11Nm2kg−2      2×1030kg.G =6.67×10-11Nm2kg-2

 14.8 km

7.2 km

14.2 km

15.8 km

  1. 5N āĻāĻŦāĻ‚ 10N āĻŽāĻžāύ⧇āϰ āĻĻ⧁āϟāĻŋ āĻŦāϞ āĻāĻ•āϟāĻŋ āĻ•āĻŖāĻžāϰ āωāĻĒāϰ āφāϰ⧋āĻĒāĻŋāϤ āĻšāϞ⧇, āύāĻŋāĻŽā§āύ⧇āϰ āϕ⧋āύ āĻŦāϞāϟāĻŋ āĻ•āĻŖāĻžāϟāĻŋāϰ āωāĻĒāϰ āϞāĻŦā§āϧāĻŋ āĻŦāϞ āĻšāϤ⧇ āĻĒāĻžāϰ⧇ āύāĻž?

5N

10N

15 N

 20 N

  1. āϕ⧋āύ āϏāĻŋāĻ¸ā§āĻŸā§‡āĻŽ 1500J āϤāĻžāĻĒ āĻļā§‹āώāĻŖ āĻ•āϰ⧇ āĻāĻŦāĻ‚ 82J āĻ•āĻžāϜ āϏāĻŽā§āĻĒāĻžāĻĻāύ āĻ•āϰ⧇āĨ¤ āϏāĻŋāĻ¸ā§āĻŸā§‡āĻŽā§‡āϰ āĻ…āĻ¨ā§āϤāσāĻ¸ā§āĻĨ āĻļāĻ•ā§āϤāĻŋāϰ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāύ āĻšāĻŦ⧇ –

 1418J

1232 J

1582 J

1237 J

  1. āĻāĻ•āϟāĻŋ 60W āĻŦ⧈āĻĻā§āϝ⧁āϤāĻŋāĻ• āĻŦāĻžāϤāĻŋāϕ⧇ 220 V s āϤ⧜āĻŋā§Ž āϏāϰāĻŦāϰāĻžāĻš āĻ‰ā§ŽāϏ⧇āϰ āϏāĻ‚āϗ⧇ āϏāĻ‚āϝ⧁āĻ•ā§āϤ āĻ•āϰāĻž āĻšāϞāĨ¤ āϐ āĻŦāĻžāϤāĻŋāϤ⧇ āĻ•āĻŋ āĻĒāϰāĻŋāĻŽāĻžāĻŖ āϤ⧜āĻŋā§Ž āĻĒā§āϰāĻŦāĻžāĻšāĻŋāϤ āĻšāĻŦ⧇?

 0.2727A

2.727A

0.2727 A

2.727 A

  1. 24400 J āĻ—āϤāĻŋāĻļāĻ•ā§āϤāĻŋ āĻŦāĻŋāĻļāĻŋāĻˇā§āϟ āĻāĻ•āϟāĻŋ āϚāĻžāĻ•āĻž āĻĒā§āϰāϤāĻŋ āĻŽāĻŋāύāĻŋāĻŸā§‡ 602 āĻŦāĻžāϰ āĻ˜ā§‹āϰ⧇ āĨ¤ āϚāĻžāĻ•āĻžāϟāĻŋāϰ āĻ˜ā§‚āĻ°ā§āĻŖāύ āϜ⧜āϤāĻž āĻšāĻŦ⧇ –

40.5kgm240.5kgm2

  12.3kgm2    12.3kgm2

10kgm2 10kgm2

406.7 kgm2 406.7 kgm2

  1. 5g āĻ­āϰ⧇āϰ āϏāĻŽāϤ⧁āĻ˛ā§āϝ āĻļāĻ•ā§āϤāĻŋ āĻ•āϤ?

15 ×108J15 ×108J

     4.5×1014J    4.5×1014J

3×1014J        3×1014J

45×1014J   45×1014J

  1. āϭ⧇āĻ•ā§āϟāĻ°â†’A=i∧−3j∧+5k∧→A=i∧-3j∧+5k∧    āĻāĻŦāĻ‚Â Â Â Â Â Â â†’B=ai∧+6j∧−10k∧     →B=ai∧+6j∧-10k∧ ,a -āĻāϰ āĻŽāĻžāύ āĻ•āϤ āĻšāϞ⧇ āϭ⧇āĻ•ā§āϟāϰ āĻĻ⧁āϟāĻŋ āϏāĻŽāĻžāĻ¨ā§āϤāϰāĻžāϞ āĻšāĻŦ⧇?

 -2

-1

1

  1. āĻāĻ•āϟāĻŋ āϏāĻŽāϤāϞ āύāĻŋāσāϏāϰāĻŖ āĻ—ā§āϰ⧇āϟāĻŋāĻ‚ āĻ 600×10−9m×10-9m āϤāϰāĻ™ā§āĻ—āĻĻ⧈āĻ°ā§āĻ˜ā§āϝāϰ āφāϞ⧋āĻ• āϰāĻļā§āĻŽāĻŋ āĻĒā§āϰāĻĨāĻŽ āĻ•ā§āϰāĻŽā§‡Â 30°   30°    āϕ⧋āϪ⧇ āĻ…āĻĒāĻŦāĻ°ā§āϤāĻŋāϤ āĻšāϞ⧇ āĻ—ā§āϰ⧇āϟāĻŋāĻ‚ āĻāϰ āĻĒā§āϰāϤāĻŋ āĻŽāĻŋāϟāĻžāϰ⧇ āϰ⧇āĻ–āĻžāϰ āϏāĻ‚āĻ–ā§āϝāĻž āĻ•āϤ?

6.25×105m−1     6.25×105m-1

8.0×105m−1    8.0×105m-1

7.85×105m−1  7.85×105m-1

     8.33×105 m−1    8.33×105 m-1

  1. āĻāĻ•āϟāĻŋ āϏāϰāϞ āĻĻā§‹āϞāϕ⧇āϰ āĻĻā§‹āϞāύāĻ•āĻžāϞ T āĨ¤ āĻĻā§‹āϞāĻ•āϟāĻŋāϰ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻĻā§āĻŦāĻŋāϗ⧁āĻŖ āĻ•āϰāĻž āĻšāϞ⧇ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤāĻŋāϤ āĻĻā§‹āϞāύāĻ•āĻžāϞ āĻšāĻŦ⧇ –

1√2  T    12  T

12T12T

2T      2T

  √2T 2T

  1. āĻāĻ•āϟāĻŋ āĻŦāĻ¸ā§āϤ⧁āϰ āĻ­āϰ āĻŦāĻžāϤāĻžāϏ⧇ 100 g āĻ“ āĻ…ā§āϝāĻžāϞāϕ⧋āĻšāϞ⧇ 84 g āĨ¤ āĻ…ā§āϝāĻžāϞāϕ⧋āĻšāϞ⧇āϰ āϘāύāĻ¤ā§āĻŦ 0.8g/cc āĻšāϞ⧇ āĻŦāĻ¸ā§āϤ⧁āϰ āĻ†ā§ŸāϤāύ āĻ•āϤ?

12.5 cc

 20 cc

16 cc

10.5 sec

  1. āĻāĻ•āϟāĻŋ āĻ•āĻŽāύ -āĻŦ⧇āϏ āĻŸā§āϰāĻžāύāϜāĻŋāĻ¸ā§āϟāϰ āĻŦāĻŋāĻ¨ā§āϝāĻžāϏ⧇ āĻāĻŽāĻŋāϟāϰ āĻ•āĻžāϰ⧇āĻ¨ā§āϟ 1.2 mA āĻāĻŦāĻ‚ āĻ•āĻžāϞ⧇āĻ•ā§āϟāϰ āĻ•āĻžāϰ⧇āĻ¨ā§āϟ

0.3 ×10−3      0.3 ×10-3

 9 ×10−4 A9 ×10-4 A

3×103A 3×103A

0.3 ×103  A      0.3 ×103  A

  1. āĻ¸ā§āĻĨāĻŋāϰ āĻ…āĻŦāĻ¸ā§āĻĨāĻžāύ āĻĨ⧇āϕ⧇ āĻāĻ•āϟāĻŋ āĻŸā§āϰ⧇āύ10ms210ms2āϏāĻŽāĻ¤ā§āĻŦāϰāϪ⧇ āϚāϞāĻžāϰ āϏāĻŽā§Ÿ 125m āĻĻā§‚āϰāĻ¤ā§āĻŦ⧇ āĻ…āĻŦāĻ¸ā§āĻĨāĻŋāϤ āĻāĻ•āϟāĻŋ āĻĒā§‹āĻˇā§āϟāϕ⧇ āĻ•āϤ āĻŦ⧇āϗ⧇ āĻ…āϤāĻŋāĻ•ā§āϰāĻŽ āĻ•āϰāĻŦ⧇?

2500ms−1     2500ms-1

10ms−1  10ms-1

10ms−1 10ms-1

      50ms−1     50ms-1

  1. āĻ­ā§‚-āĻĒ⧃āĻˇā§āĻ  āĻšāϤ⧇ āĻ…āĻ˛ā§āĻĒ āωāĻšā§āϚāϤāĻžā§Ÿ āĻāĻŦāĻ‚ āĻ­ā§‚-āĻĒ⧃āĻˇā§āĻ āϰ āϏāĻŽāĻžāĻ¨ā§āϤāϰāĻžāϞ āĻāĻ•āϟāĻŋ āύāĻ­ā§‹āϝāĻžāύ āĻ•āϤ āĻĻā§āϰ⧁āϤāĻŋāϤ⧇ āϚāϞāϞ⧇ āϝāĻžāĻ¤ā§āϰ⧀āϰāĻž āĻ“āϜāĻšā§€āύāϤāĻž āĻ…āύ⧁āĻ­āĻŦ āĻ•āϰāĻŦ⧇? [āĻĒ⧃āĻĨāĻŋāĻŦā§€āϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ= 6400 km āĻāĻŦāĻ‚g=9.8 ms−2]g=9.8 ms-2]

 7.9kms−1  7.9kms-1

7.1kms−1 7.1kms-1

3.5 kms−1     3.5 kms-1

3.1 kms−1 3.1 kms-1

  1. āĻāĻ•āϟāĻŋ āĻšā§āχāϟāĻ¸ā§āĻŸā§‹āύ āĻŦā§āϰ⧀āĻœā§‡āϰ āϚāĻžāϰāϟāĻŋ āĻŦāĻžāĻšā§āϤ⧇ āϝāĻĨāĻžāĻ•ā§āϰāĻŽā§‡ 6, 18, 10 āĻāĻŦāĻ‚ ⧍ā§Ļ āĻ“āĻšāĻŽā§‡āϰ āϰ⧋āϧ āĻļā§āϰ⧇āĻŖā§€ āϏāĻŽāĻŦāĻžā§Ÿā§‡ āϝ⧁āĻ•ā§āϤ āĻ•āϰāϞ⧇ āĻŦā§āϰ⧀āϜāϟāĻŋāĻž āϏāĻžāĻŽā§āϝāĻžāĻŦāĻ¸ā§āĻĨāĻž āĻĒā§āϰāĻžāĻĒā§āϤ āĻšāĻŦ⧇?

20 omega

30 omega

 10 omega

40 omega

  1. 1.0 m āĻĻā§€āĻ°ā§āϘ āĻ“ 1.0 mm āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ⧇āϰ āĻŦ⧇āϞāύāĻžāĻ•āĻžāϰ āϤāĻžāϰ⧇āϰ āωāĻĒāϰ 100N āĻŦāϞ āĻĒā§āĻ°ā§Ÿā§‹āĻ— āĻ•āϰāϞ⧇ āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻŦ⧃āĻĻā§āϧāĻŋ āĻĒā§‡ā§Ÿā§‡ 1.001 m āĻšā§ŸāĨ¤ āϤāĻžāϰ⧇āϰ āĻ‡ā§ŸāĻ‚ āĻāϰ āϗ⧁āĻŖāĻžāĻ‚āĻ• āĻ•āϤ?

 1Ī€Ã—1011 Nm−21Ī€Ã—1011 Nm-2

1011 Nm−2       1011 Nm-2

Ī€Ã—1011Nm−2Â Â Â Â Â Ī€Ã—1011Nm-2

Ī€2×1011Nm−2Â Ī€2×1011Nm-2

  1. āĻāĻ•āϟāĻŋ āϏāĻŽāĻžāĻ¨ā§āϤāϰāĻžāϞ āĻĒāĻžāϤ āϧāĻžāϰāĻ•āϕ⧇ āϚāĻžāĻ°ā§āϜāĻŋāϤ āĻ•āϰāĻžāϰ āĻĢāϞ⧇ āĻĒāĻžāϤāĻĻā§āĻŦā§Ÿā§‡āϰ āĻŽāĻ§ā§āϝ⧇ āĻŦāĻŋāĻ­āĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻ•ā§āϝ āĻšāϞ V āĨ¤ āĻŦāĻŋāĻ­āĻŦ āĻĒāĻžāĻ°ā§āĻĨāĻ•ā§āϝ āĻ•āϤ āĻšāϞ⧇ āϧāĻžāϰāϕ⧇āϰ āϏāĻžā§āϚāĻŋāϤ āĻļāĻ•ā§āϤāĻŋ āĻĻā§āĻŦāĻŋāϗ⧁āĻŖ āĻšāĻŦ⧇?

14V  14V

12 V  12 V

  √2v 2v

2v 2v

  1. āĻŦāĻžā§Ÿā§ āĻĨ⧇āϕ⧇ āĻ…āĻ¨ā§āϝāϕ⧋āύ āĻŽāĻžāĻ§ā§āϝāĻŽā§‡āϰ āĻ­āĻŋāϤāϰ āĻāĻ•āϟāĻŋ āφāϞ⧋āĻ• āϰāĻļā§āĻŽāĻŋ āĻĒā§āϰāĻŦ⧇āĻļ āĻ•āϰāĻžāϰ āĻĒāϰ āϤāĻžāϰ āĻ—āϤāĻŋ 15% āĻšā§āϰāĻžāϏ āĻĒāĻžā§ŸāĨ¤ āϐ āĻŽāĻžāĻ§ā§āϝāĻŽā§‡āϰ āĻĒā§āϰāϤāĻŋāϏāϰāĻžāĻ‚āĻ• āĻšāϞ –

1.5

1.33

1.61

 1.18

  1. āϕ⧋āύ āϧāĻžāϤ⧁āϰ āĻ•āĻžāĻ°ā§āϝ āĻ…āĻĒ⧇āĻ•ā§āώāĻ•3.2×10−19J3.2×10-19J   āĨ¤ āϐ āϧāĻžāϤ⧁āĻ¤ā§‡Â Â Â Â Â 4500 A°    4500 A°āϤāϰāĻ™ā§āĻ— āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ⧇āϰ āφāϞ⧇āĻ• āϰāĻļā§āĻŽāĻŋ āφāĻĒāϤāĻŋāϤ āĻšāϞ⧇ āύāĻŋāσāϏ⧃āϤ āχāϞ⧇āĻ•ā§āĻŸā§āϰāύ⧇āϰ āϏāĻ°ā§āĻŦā§‹āĻšā§āϚ āĻ—āϤāĻŋāĻļāĻ•ā§āϤāĻŋ āύāĻŋāĻ°ā§āϪ⧟ āĻ•āϰāĨ¤ āĻĒā§āϞāĻžāĻ™ā§āϕ⧇āϰ āĻ§ā§āϰ⧁āĻŦāϕ⧇āϰ āĻŽāĻžāύ =    6.63 ×10−34Js    6.63 ×10-34Js

0.8×10−19J    0.8×10-19J

2.4×10−19 J   2.4×10-19 J

1.0 ×10−19J  1.0 ×10-19J

 1.2 ×10−19J1.2 ×10-19J

  1. āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āϏāĻ‚āϕ⧋āϚāύ⧇āϰ āϏāĻŽā§€āĻ•āϰāĻŖ āĻšāϞ –

L=L√1−v2c2 L=L1-v2c2

    L =L0√1−v2c2   L =L01-v2c2

L=L√1+v2c2  L=L1+v2c2

L=L0 √1+v2c2 L=L0 1+v2c2

  1. āĻĢ⧇āϰ⧋āϚ⧌āĻŽā§āĻŦāĻ• āϝ⧇ āϤāĻžāĻĒāĻŽāĻžāĻ¤ā§āϰāĻžā§Ÿ āĻĒā§āϝāĻžāϰāĻžāϚ⧌āĻŽā§āĻŦāĻ• āĻĒāϰāĻŋāĻŖāϤ āĻšā§Ÿ āϤāĻžāϕ⧇ āĻŦāϞāĻž āĻšā§Ÿ –

Debye temperature

Neel temperature

 Curie temperature

None of these

  1. āĻāĻ•āϟāĻŋ āĻŸā§āϰ⧇āύ āĻšā§āχāϏ⧇āϞ āĻŦāĻžāϜāĻŋā§Ÿā§‡90 kmh−190 kmh-1    āĻŦ⧇āϗ⧇ āĻĒā§āϞāĻžāϟāĻĢāϰāĻŽā§‡āϰ āĻĻāĻŋāϕ⧇ āĻ…āĻ—ā§āϰāϏāϰ āĻšāĻšā§āϛ⧇āĨ¤ āĻĒā§āϞāĻžāϟāĻĢāϰāĻŽā§‡ āĻ…āĻŦāĻ¸ā§āĻĨāĻŋāϤ āϝāĻžāĻ¤ā§āϰ⧀ 650 Hz āĻ•āĻŽā§āĻĒāĻžāĻ™ā§āϕ⧇ āĻļāĻŦā§āĻĻ āĻļ⧁āύāϤ⧇ āĻĒāĻžā§ŸāĨ¤ āĻšā§āχāϏ⧇āϞ⧇āϰ āĻĒā§āϰāĻ•ā§ƒāϤ āĻ•āĻŽā§āĻĒāĻžāĻ‚āĻ• āĻ•āϤ? ( āĻŦāĻžā§Ÿā§āϤ⧇ āĻļāĻŦā§āĻĻ⧇āϰ āĻĻā§āϰ⧁āϤāĻŋ =        325ms−1        325ms-1)

 600 Hz

90 Hz

550 Hz

320 Hz

  1. āχāĻ‚ā§Ÿ āĻāϰ āĻĻā§āĻŦāĻŋ-āϚāĻŋ⧜ āĻĒāϰ⧀āĻ•ā§āώāĻŖ āϚāĻŋ⧜ āĻĨ⧇āϕ⧇ 1 m āĻĻā§‚āϰ⧇ āĻāĻ•āϟāĻŋ āωāĻœā§āϜāϞ āĻĄā§‹āϰāĻžāϰ āĻĒā§āϰāĻ¸ā§āĻĨ 0.5 mm āĨ¤ āϚāĻŋ⧜ āĻĻ⧁āϟāĻŋāϰ āĻŽāĻ§ā§āϝ⧇ āĻĻā§‚āϰāĻ¤ā§āĻŦ⧇ 0.2 mm āĻšāϞ⧇ āφāϞ⧋āϰ āϤāϰāĻ™ā§āĻ—āĻĻ⧈āĻ°ā§āĻ˜ā§āϝ āĻ•āϤ?

0.5 mm

0.2 mm

 10−7m10-7m

10−7nm    10-7nm

  1. āĻšāĻžāχāĻĄā§āϰ⧋āĻœā§‡āύ āĻĒāϰāĻŽāĻžāϪ⧁āϰ āĻĒā§āϰāĻĨāĻŽ āĻŦā§‹āϰ āĻ•āĻ•ā§āώ⧇ āχāϞ⧇āĻ•āĻŸā§āϰāύ⧇āϰ āĻŽā§‹āϟ āĻļāĻ•ā§āϤāĻŋ -13.6 eV āĻšāϞ⧇, āϤ⧃āĻ¤ā§€ā§Ÿ āĻŦā§‹āϰ āĻ•āĻ•ā§āώ⧇ āĻŽā§‹āϟ āĻļāĻ•ā§āϤāĻŋ āĻšāĻŦ⧇-

40.8 eV

-4.5 eV

-3.4eV

 -1.5eV

  1. āϚāĻŋāĻ¤ā§āϰ⧇ āĻĻ⧇āĻ–āĻžāύ⧋ āĻŦāĻ°ā§āϤāύ⧀ āĻĻāĻŋā§Ÿā§‡ āĻĒā§āϰāĻŦāĻžāĻšāĻŋāϤ āĻ•āĻžāϰ⧇āĻ¨ā§āϟāϰ āĻŽāĻžāύ āĻ•āϤ?

3.0 A

  1. 25 A

 2.0 A

1.5 A

  1. āĻ•ā§āϝāĻžāĻĨā§‹āĻĄ āϰāĻļā§āĻŽāĻŋāϰ āĻ•ā§āώ⧇āĻ¤ā§āϰ⧇ āύāĻŋāĻšā§‡āϰ āϕ⧋āύ āϧāĻ°ā§āĻŽāϟāĻŋ āϏāĻ¤ā§āϝ āύ⧟?

āĻ•ā§āϝāĻžāĻĨā§‹āĻĄ āϰāĻļā§āĻŽāĻŋāϰ āϏāϰāϞāϰ⧇āĻ–āĻžā§Ÿ āĻ—āĻŽāύ āĻ•āϰ⧇

 āĻ•ā§āϝāĻžāĻĨā§‹āĻĄ āϰāĻļā§āĻŽāĻŋ āĻĒāϰāĻ¸ā§āĻĒāϰāϕ⧇ āφāĻ•āĻ°ā§āώāĻŖ āĻ•āϰ⧇

āĻ•ā§āϝāĻžāĻĨā§‹āĻĄ āϰāĻļā§āĻŽāĻŋ āϤāĻžāĻĒ āĻ‰ā§ŽāĻĒāĻžāĻĻāĻžāύ āĻ•āϰ⧇

āĻ•ā§āϝāĻžāĻĨā§‹āĻĄ āϰāĻļā§āĻŽāĻŋ āĻĢāĻŸā§‹āĻ—ā§āϰāĻžāĻĢāĻŋāĻ• āĻĒā§āϞ⧇āĻŸā§‡āϰ āωāĻĒāϰ āĻ•ā§āϰāĻŋ⧟āĻž āĻ•āϰ⧇

  1. 300 Nm−1 Nm-1   āĻŦāϞ āĻ§ā§āϰ⧁āĻŦāϞ āϏāĻŽā§āĻĒāĻ¨ā§āύ āĻāĻ•āϟāĻŋ āĻ¸ā§āĻĒā§āϰāĻŋāĻ‚āϕ⧇ āĻ•āϤāϟ⧁āϕ⧁ āϏāĻ‚āϕ⧁āϚāĻŋāϤ āĻ•āϰāϞ⧇ 1.5 J āĻ•āĻžāϜ āĻ•āϰāĻž āĻšāĻŦ⧇?

 0.1m

1.5 m

3.01

1.0m

  1. āĻāĻ•āϟāĻŋ āĻ•āĻžāĻ°ā§āύ⧋ āχāĻžā§āϜāĻŋāύ āĻĒāĻžāύāĻŋāϰ āĻšāĻŋāĻŽāĻžāĻ™ā§āĻ• āĻ“ āĻ¸ā§āĻĢ⧁āϟāύāĻžāĻ‚āϕ⧇āϰ āĻŽāĻ§ā§āϝ⧇ āĻ•āĻžāĻ°ā§āϝāϰāϤ āφāϛ⧇āĨ¤ āχāĻžā§āϜāĻŋāύāϟāĻŋāϰ āĻĻāĻ•ā§āώāϤāĻž āĻ•āϤ?

100%

0%

 26.8%

28.6%

  1. āĻāĻ•āϟāĻŋ āĻĻāĻŋāĻŦ āĻĒāϰāĻŋāĻŦāĻ°ā§āϤ⧀ āĻĒā§āϰāĻŦāĻžāĻšāϕ⧇ I =100 sin 500΀΀t āϏāĻŽā§€āĻ•āϰāĻŖ āĻĻā§āĻŦāĻžāϰāĻž āĻĒā§āϰāĻ•āĻžāĻļ āĻ•āϰāĻž āϝāĻžā§ŸāĨ¤ āϐ āĻĒā§āϰāĻŦāĻžāĻšā§‡āϰ āĻ•āĻŽā§āĻĒāĻžāĻ‚āĻ• āĻ•āϤ?

200Hz

 250 Hz

300 Hz

500 Hz

  1. āĻāĻ•āϟāĻŋ āĻ…āĻŦāϤāϞ āĻĻāĻ°ā§āĻĒāϪ⧇āϰ āĻŦāĻ•ā§āϰāϤāĻžāϰ āĻŦā§āϝāĻžāϏāĻžāĻ°ā§āϧ⧁ 30 cm āĨ¤ āĻāĻ•āϟāĻŋ āĻŦāĻ¸ā§āϤ⧁āϕ⧇ āĻŦāĻ•ā§āϰāϤāĻžāϰ āϕ⧇āĻ¨ā§āĻĻā§āϰ⧇ āϰāĻžāĻ–āϞ⧇ āĻāϰ āĻĒā§āϰāϤāĻŋāĻŦāĻŋāĻŽā§āĻŦ⧇āϰ āĻĻā§‚āϰāĻ¤ā§āĻŦ āĻ•āϤ?

15 cm

45 cm

 30 cm

60 cm

āύāĻŋāĻœā§‡āϰ āϏ⧁āĻŦāĻŋāϧāĻžāĻŽāϤ āĻĒ⧜āĻžāϰ āϜāĻ¨ā§āϝ āϟāĻžāχāĻŽāϞāĻžāχāύ⧇ āĻļā§‡ā§ŸāĻžāϰ āĻ•āϰ⧇ āϰāĻžāϖ⧁āύ

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